`6x^2+17x+12`

Factorise 6x^2 + 17x + 5 by splitting the middle term method.

6x^2+17x+5 =

Factorise: 6x ^(2) - 17x -3

If f(x)=2x^(3)-13x^(2)+17x+12; Find f(-1) and f(2)

Factorise 6x^(2) + 17x + 5 by splitting the middle term, and by using the factor theorem.

If f(x)=2x^(3)-13x^(2)+17x+12, find f(2) (ii) f(-3)

If f(x)=2x^(3)-13x^(2)+17x+12 , then find the value of f(-2) and f(3).

A function F is defined as follow : for x gt 0, F(x) = x^6- x^3- 17x - 17 for x lt 0, F(x) = -x^6-x^2+17x-17 What is the value of F (-1) ?

Solve the following quadratic equation by factorization method: 6x^(2)-17ix-12=0