An electron moving with a speed of `5xx10^(6)m//s` is shot parallel to the electric field of strength `1xx10^(3)` N/C arranged so as to retard its motion. How far will the electron travel in the field before coming (momentarily) to rest? (`m_(e)=9.1xx10^(-31)kg`)

An electron with a speed of 2.60 xx 10^(8) cm//s enters and electric field of magnitude 1.00 xx 10^(3)N//C , travelling along a field in the direction that retards its motion. (a) How far will the electron travel in the field before stopping momentarily, and (b) how much time will have elapsed ? (c ) If the region containing the electric field is 8.00 mm long (too short for the electroc to stop within it),what fraction of the electrons initial energy will be lost in that region ?

An electron moving with the speed 5xx10^(6) per sec is shot parallel to the electric field of intensity 1xx10^(3)N//C . Field is responsible for the retardation of motion of electron. Now evaluate the distance travelled by the electron before coming to rest for an instant (mass of e= 9xx10^(-31)Kg charge = 1.6xx10^(-19)C)

An electron moving with the speed 5xx10^(6) per sec is shot parallel to the electric field of intensity 1xx10^(3)N//C . Field is responsible for the retardation of motion of electron. Now evaluate the distance travelled by the electron before coming to rest for an instant (mass of e= 9xx10^(-31)Kg charge = 1.6xx10^(-19)C)

An electron moving with the speed 5xx10^(6) per sec is shot parallel to the electric field of intensity 1xx10^(3)N//C . Field is responsible for the retardation of motion of electron. Now evaluate the distance travelled by the electron before coming to rest for an instant (mass of e= 9xx10^(-31)Kg charge = 1.6xx10^(-19)C)

An electron with a speed 5.00xx10^6 m/s enters an electric field of magnitude 10^3 N/C, travelling along the field lies in the direction that retards its motion. a. How far will the electron travel in the field before stopping momentarily? b. How much time will have elapsed? c. If the regin with the electric field is only 8.00 mm long (too short from the electronn to stop with in it), what fraction of the elctron's initial kinetic energy wil be lost in that region.

An electron with a speed 5.00xx10^6 m/s enters an electric field of magnitude 10^3 N/C, travelling along the field lies in the direction that retards its motion. a. How far will the electron travel in the field before stopping momentarily? b. How much time will have elapsed? c. If the regin with the electric field is only 8.00 mm long (too short from the electronn to stop with in it), what fraction of the elctron's initial kinetic energy wil be lost in that region.

An electron moving with the speed 5 xx 10^6 m per second is shooted parallel to the electric field of intensity 1 xx 10^3 N/C. Field is responsible for the retardation of motion of electron. Now evaluate the distance travelled by the electron before coming to rest for an instant, (mass of e = 9.1 xx 10^(-31) kg)

An electron is released with a velocity of 5xx10^(6)ms^(-1) in an electric field of 10^(3)NC^(-1) which has been applied so as to oppose its motion. What distance would the electron travel and how much time could it take before it is brought to rest?

An electron travelling with a speed of 5 xx 10^3 m/s passes through an electric field with an acceleration of 10^12 ms^-2 . How long will it take for electron to double its speed?