If `cosptheta=cosqtheta, pneq,` then

Select the correct option from the given alternatives: If cosptheta = cosqtheta , p neq : A) theta = frac{2npi}{p pm q} B) theta = 2npi C) theta =2npi pm p D) theta=npi pm q

Solve: cosptheta+cosqtheta=0

Solve: cosptheta+cosqtheta=0

If tanptheta= cotqtheta and pneq show that the solutions are in A.P with common difference (pi)/(p+q)

If x=sintheta , y=cosptheta , prove that (1-x^2)y_2-x y_1+p^2y=0 , where y_2=(d^2y)/(dx^2) and y_1=(dy)/(dx) .

Given pnepmq . Show that the solutions of cosPtheta+cosqtheta=0 form two series each of which is in A.P . Find also the common difference of each A.P .

If x=sin theta,y=cosptheta,p rov e \ t h a t (1-x^2)y_2-x y_1+p^2y=0,w h e r e \ y_2=(d^2y)/(dx^2) \ a n d \ y_1=(dy)/(dx)

If x=sintheta" and "y=cosptheta , p is constant, prove that (1-x^(2))y_(2)-xy_(1)+p^(2)y=0.

Find the general value of theta from the equation sinptheta=cosqtheta .