`sin2theta - cos2theta =1`

Find the general solutions of the following equations: sin^2theta -cos^2theta = 1

If theta be any real, prove that : cos4 theta=1-8 sin^2 theta cos^2 theta =1-8 cos^2 theta +8 cos^4 theta .

prove that sin^2theta+cos^2theta=1

(1+sin 2theta+cos 2theta)/(1+sin2 theta-cos 2 theta) =

(1+sin 2theta+cos 2theta)/(1+sin2 theta-cos 2 theta) =

If sin^2theta-cos^2theta=1 then find the principal value of theta

Prove the following sin^4theta-cos^4theta=sin^2theta-cos^2theta=1-2cos^2theta=2sin^2theta-1

Assertion: sin2theta=(2tantheta)/(1+tan^2 theta) , Reason: sin^2 theta +cos^2 theta =1,sin2theta=2sinthetacostheta

prove : sin^8θ-cos^8θ = (sin^2 theta - cos^2 theta) (1- 2 sin^2 theta cos^2 theta)