Area of a regular polygon of n sides is given by A=`n(sqrt(3))/(4)a^(2)sq`. Units . Make 'a' the subject of the formula and find 'a' if the area of a hexagon is `54sqrt(3)` sq. units.

The area of a regular hexagon of side 2sqrt3 cm is :

The area of a regular hexagon of side 2sqrt(3) cm is :

In Fig. 3, the area of triangle ABC (in sq. units) is :

What is the area (in sq cm.) of the regular hexagon side 14 cm ?

If the angles of a triangle are 30^0a n d45^0 and the included side is (sqrt(3)+1) cm, then area of the triangle is 1/2(sqrt(3)+1)sq units area of the triangle is 1/2(sqrt(3)-1)sq units

The maximum area of a triangle inscribed in a circle is a circle of radius r is (3sqrt3)/4r^2 sq. units

In Fig.3, the area of triangle ABC( in sq.units ) is :