Lets be the sum of the digits of the number `15^(2)xx5^(18)` in base 10. Then

The sum of a two digit number and the number formed by interchanging the digits is 110. If 10 is subtracted from the first number, the new number is 4 more than 5 times the sums of the digits of the first number. Find the first number.

The sum of the digits of a two-digit number is 12. if 18 is subtracted from the number, then the digits interchange their places. Find the number. The following steps are involved in solving the above problem. Arrange them in sequential order. (A) Units digits is 5, tens digit is 7, and the number is 75. (B) Given that 120-9x-18=9x+12rArr90=18xrArrx=5 . (C) The number formed by interchanging the digits is 10x+(12-x)=9x+12 . (D) Let the digit in the units place be x. Then the digit in the tens place be (12-x). therefore The number is 10(12-x)+x=120-10x+x=120-9x .

The sum of the digits of a two digit number is 10. If 18 is subtracted from the number, digits are reversed. Find the numbers.

The sum of the digits of a two digit number is 10. If 18 is subtracted from the number, digits are reversed. Find the numbers.

The digit of a 2-digit number in a unit is 5 and the sum of the digits is the (1/5) of the original number Find the number.

A number of two digits is 3 more than 4 times of the sum of its digits. If the positions of the digits of the number be interchanged , then the new number thus formed is 18 more than the original number. Determine the number.