`i^(243)=`

sqrt(27) + sqrt(243) =

In which octant does the given point lie? (i) (-2,4,3) " " (ii) (3,-2,-5) " " (iii) (-6,3,-4) (iv) (-3,-1,4) " " (v) (1,-3,6) " " (4,7,-2)

The value of expression ((243+647)^(2) +(243-647)^(2))/(243 xx 243 +647xx647) is equal to

Verify: (243) times (-51)=(-243) times 51

Verify: (243) times (-51)=(-243) times 51

(32/243)^(3//5) = ?

Solve : sqrt(243) - sqrt(108)

root(5)((32)/(243)) is a surd