A particle is moving along X-axis Its acceleration at time t is proportional to its velocity at that time. The differential equation of the motion of the particle is

If a particle moves along a line by S = sqrt(1 + t) then its acceleration is proportional to _______ of its velocity at the instant.

Statement I : A particle moving with uniform acceleration has its displacement proportional to the square of time. Statement II : If the motion of a particle is represented by a straight line on the velocity -time graph its acceleration is uniform.

A particle is moving along x -axis with a uniform positive acceleration.Draw the position time graph for its motion.

A particle moves along x-axis and its acceleration at any time t is a = 2 sin ( pit ), where t is in seconds and a is in m/ s^2 . The initial velocity of particle (at time t = 0) is u = 0. Q. Then the magnitude of displacement (in meters) by the particle from time t = 0 to t = t will be :

A particle moves along x-axis and its acceleration at any time t is a = 2 sin ( pit ), where t is in seconds and a is in m/ s^2 . The initial velocity of particle (at time t = 0) is u = 0. Q. Then the distance travelled (in meters) by the particle from time t = 0 to t = t will be :

A particle moves along x-axis and its acceleration at any time t is a = 2 sin ( pit ), where t is in seconds and a is in m/ s^2 . The initial velocity of particle (at time t = 0) is u = 0. Q. Then the distance travelled (in meters) by the particle from time t = 0 to t = 1 s will be :

A partiole is moving in a straight line such that its velocity at time t is proportional to t^(5) . Then its acceleration is proportional to

A particle is moving along the x-axis and its position-time graph is shown. Determine the sign of acceleration.

A particle is moving along the x-axis and its position-time graph is shown. Determine the sign of acceleration.