Find the slope of the normal to the curve `x = 1 - a sin theta, y = b cos^(2) theta` at `theta = (pi)/2`.

Find the slope of the normal to the curve x=1-a sin theta,y=b cos^(2)theta at quad theta=(pi)/(2)

Find the slope of the normal to the curve x=1-a sin^(3) theta, y=a cos^(2)theta" at "theta=(pi)/(2) .

Find the slope of the normal to the curve x = a cos^(3)theta, y = a sin^(3) theta at theta = (pi)/3 .

The slope of tangent to the curve x= 1-a sin theta, y = b cos^(2) theta" at "theta = (pi)/(2) is:

Find the slope of the tangent to the curve: x = 1-a sintheta, y = b cos^2 theta at theta = pi/2

Find the slope of the normal to the curve x = a cos^(3) theta, y = a sin^(3) theta at theta = (pi)/(4) . A) 0 B) -1 C) 1 D) none of these