If the sum of the squares of the sides of a triangle ABC is equal to twice the square of its circum diameter, then `sin^2A+sin^2B+sin^2C`=

If the sum of the squares of the sides of a triangles ABC is equal to twice the square of its circum diameter , then sin ^(2) A + sin ^(2) B + sin ^(2) C =

A triangle ABC is inscribed in a circle. If sum of the squares of sides of the triangle is equal to twice the square of the diameter then sin^2A+sin^2B+sin^2C is equal to

A triangle ABC is inscirbed in a circle. If half the sum of the square of its three sides is equal to twice the square of the diameter of the circle, then the value of sin^(2)A + sin^(2)B + sin^(2)C will be-

IF twice the square of the radius of a circle is equal to half the sum of the squares of the sides of inscribed triangle ABC, then sin^2 A+sin^2 B+sin^2 C=

If twice the square of the diameter of a circle is equal to half the sum of the square of the sides of inscribed Delta ABC, then sin^2A+sin^2B++sin^2C is equal to:

If twice the square of the diameter of the circle is equal to half the sum of the squares of the sides of incribed triangle ABC,then sin^(2)A+sin^(2)B+sin^(2)C is equal to

If twice the square of the diameter of the circle is equal to half the sum of the squares of the sides of incribed triangle ABC,then sin^(2)A+sin^(2)B+sin^(2)C is equal to

If twice the square of the diameter of the circle is equal to half the sum of the squares of the sides of incribed triangle ABC,then sin^(2)A+sin^(2)B+sin^(2)C is equal to