The conductivity of `"0.001028 mol.L"^(-1)` acetic acid is `4.95xx10^(-5)"S.cm"^(-1)`. Calculate its dissociation constant if `Lambda_(m)^(@)` for acetic acid is `"390.5 S.cm"^(2)."mol"^(-1)`.

The conductivity of 0.001028 mol L^(-1) acetic acid is 4.95 xx 10^(-5) S cm^(-1) . Calculate its dissociation constant if Lambda_(m)^(0) for acetic is 390.5 S cm^(2) mol^(-1) ?

Calculating the value of dissociation constant of weak electrolyte: The conductivity of 0.001028 mo L^(-1) acetic acid is 4.95 xx 10^(-5) S cm^(-1) . Calculate its dssociation constatnt if Lambda_(m)^(0) for acetic acid is 390.5 S cm^(2) mol^(-1) . Strategy: We can determine the value of the dissociation constant for week electrolytes once we know the Lambda_(m)^(0) and Lambda_(m) at any given concentration C .

The conductivity of 0.001028 mol L ^(-1) acetic acid is 4.95 xx10^(-5)S cm ^(-1). Calculate its dissociation constant if ^^(m)^(0) for acetic acid id 390.5 S cm ^(2)mol ^(-1).

The conductivity of 0.001028M acetic acid is 4.95xx10^(-5)Scm^(-1) . Calculate its dissociation constant if Lambda_(m)^(0) for acetic acid is 390.5Scm^(2)mol^(-1) .

The conductivity of 0.001028 mol L^-1 acetic acid is 4.95 xx 10^-5 Scm^-1 , Calcụlate its dissociation constint if Lambda_m^0 for acetic acid is 390.5 Scm^2 mol :

(a). The resistance of a decinormal solution of an electrolyte in a conductivity cell was found to be 245 ohms. Calculate the equilvalet conductivity of the solution if the electrodes in the cell were 2 cm apart and each has an area of 3.5 sq. cm. (b). The conductivity of 0.001028M acetic acid is 4.95xx10^(-5)Scm^(-1) . Calculate its dissociation constant if ^^_(m)^(@) for acetic acid is 390.5Scm^(2_mol^(-1)

(a). The resistance of a decinormal solution of an electrolyte in a conductivity cell was found to be 245 ohms. Calculate the equilvalet conductivity of the solution if the electrodes in the cell were 2 cm apart and each has an area of 3.5 sq. cm. (b). The conductivity of 0.001028M acetic acid is 4.95xx10^(-5)Scm^(-1) . Calculate its dissociation constant if ^^_(m)^(@) for acetic acid is 390.5Scm^(2_mol^(-1)

The conductivity of 0.001028 mol L^(-1) acetic acid is 4.95 xx 10^-5 S cm^-1 . Calculate its dissociation constant if A_m^@ for acetic acid is 390.5 S cm^2 mol^(-1).

The conductivity of 0.001028 M acetic acid is 4.95xx10^(-5) S cm^(-1) . Calculate dissociation constant if wedge_(m)^(@) for acetic acid is 390.5 S cm^(2) mol ^(-1) .