If` log10^(2) = .3010, log10^(3) = .4771` find `log_(10)36`

If log 10^(2) = 0.3010 log 10^(3) = 0.4772 find log 10^(144)

If log_(10)^(2)=0.3010,log_(10)^(3)=0.4771 then find the approv.value of log_(10)3sqrt((3^(2)x6^(4))/(sqrt(2)))

If log_(10) 2 = 0.3010 & log_(10) 3 = 0.4771 , find the value of log _(10) (2.25) .

If log_(10) 2=0.3010 then log_2 10=

If log_10 2 = 0.3010 , then log_10 32 is

Given that log_10 2=.3010 , log_10 3=.4771 ,find the value of log_10 12

If log_(10)2 = 0.3010 and log_(10)3 = 0.4771 , then find the value log_(10) 135 .

If log 2 = 0.3010 and log 3 = 0.4771, find the value of : (i) log 6 (ii) log 5 (iii) log sqrt(24)

If log 2 = 0.3010 and log 3 = 0.4771, find the value of : (i) log 12 (ii) log 1.2 (iii) log 3.6 (iv) log 15 (v) log 25 (vi) (2)/(3) log 8