` (x log x ) (dy)/(dx) + y = 2 log x `

Let y(x) be the solution of the differential equation ( x log x) (dy)/(dx) + y = 2x log x, ( x gt 1). then y (e ) is equal to :

Let y(x) be the solution of the differential equation ( x log x) (dy)/(dx) + y = 2x log x, ( x gt 1). then y (e) is equal to :

Let y(x) be the solution of the differential equation . (x log x) (dy)/(dx) + y = 2x log x, (x ge 1) . Then y (e) is equal to

Let y(x) be the solution of the differential equaiton : (x log x ) (dy)/(dx) +y=2x log x, (x ge 1) Then y(e) is equal to :

x log x(dy)/(dx) + y = (2)/(x)log x

x log x(dy)/(dx) + y = (2)/(x)log x

Solve (x log x ) ( dy)/(dx) + y = (2)/(x) log x .

Find IF x log x (dy)/(dx) + y = (2)/(x) log x .