In a cubic lattice each edge of the unit cell is 400 pm. Atomic weigth of the element is 60 and its density is` 625g//c.c.`Avogadro number =`6times10^(23)`.The crystal lattice is

Each edge of a cubic unit cell is 400pm long. If atomic mass of the elements is 120 and its desity is 6.25g//cm^(2) , the crystal lattice is: (use N_(A)=6 xx 10^(23))

Each edge of a cubic unit cell is 400pm long. If atomic mass of the elements is 120 and its desity is 6.25g//cm^(2) , the crystal lattice is: (use N_(A)=6 xx 10^(23))

An element crystallizes in a body centred cubic lattice. The edge length of the unit cell is 200 pm and the density of the element is "5.0 g cm"^(-3) . Calculate the number of atoms in 100 g of this element.

A metal crystallizes with a face-centred cubic lattice. The edge of the unit cell is 408 pm. The diameter of the metal atom is

A metal crystallizes with a face-centred cubic lattice. The edge of the unit cell is 408 pm. The diameter of the metal atom is

A metal crystallizes with a face -centred cubic lattice.The edge of the unit cells is 408 pm.The dimeter of the metal atoms is