If `f (x)= tan ^(-1) (sgn (n ^(2) -lamda x+1))` has exactly one point of discontinuity, then the value of `lamda ` can be:

f(x)=sgn(x^(2)-ax+1) has maximum number of points of discontinuity then

f(x) = sgn(x^2 - ax + 1) has maximum number of points of discontinuity then

f(x)=[2+3|n|sin x],n in N,x in(0,pi) has exactly 11 points of discontinuity Then the value of n is

If f(x)=sgn(sin^(2)x-sin x-1) has exactly four points of discontinuity for x in(0,n pi),n in N, then

If f(x) = sgn(sin^2x-sinx-1) has exactly four points of discontinuity for x in (0, npi), n in N , then

If f(x) = sgn (x) and g (x) = (1-x^2) ,then the number of points of discontinuity of function f (g (x)) is -

The points of discontinuity of f(x) = tan((pix)/(x+1))

f(x) = (x)/(1 + x tan x), x in (0, (pi)/(2)) then a)f(x) has exactly one point of minima b)f(x) has exactly one point of maxima c)f(x) is increasing in (0, (pi)/(2)) . d)f(x) is decreasing in (0, (pi)/(2)) .