If `cos 3x+sin (2x-(7pi)/6)=-2`, then x is equal to `(k in Z)`

If cos3x+sin(2x-(7pi)/6)=-2 , then x is equal to (k in Z) pi/3(6k+1) (b) pi/3(6k-1) pi/3(2k+1) (d) none of these

If cos3x+sin(2x-(7 pi)/(6))=-2, then x is equal to (k in Z)(pi)/(3)(6k+1)( b) (pi)/(3)(6k-1)(pi)/(3)(2k+1)( d ) none of these

cos3x + sin(2x- (7pi)/6)=-2

If cos 3 x + sin (2 x - (7 pi)/(6)) = - 2 then x is equal to (k in Z)

Find x cos3x+sin(2x-(7 pi)/(6))=-2

If cos3x+sin(2x-(7pi)/6)=-2 , then show that x is of the form π / 3(6m+1) .

If cos3x+sin(2x-(7pi)/6)=-2 , then show that x is of the form π / 3(6n+1) .

Let 2y={(cot^(-1)(sqrt(3)cos x-sin x))/(cos x+sqrt(3)sin x))^(2) then (dy)/(dx) is equal to (A) x-(pi)/(6)(B)x+(pi)/(6)(C)2x-(pi)/(6)(D)2x-(pi)/(3)])

lim_(x to pi)(sin 3x)/(sin 2x) is equal to