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By X-ray diffraction it is found tht nic...

By X-ray diffraction it is found tht nickel `("at mass"=59g "mol"^(-1))`, crystakkuzes with ccp. The edge length of the unit cell is `3.5 Å`. If density of Ni crystal is `9.0g//cm^(3)`, then value of Avogadro's number from the data is:

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By X-ray diffraction it is found tht nickel ("at mass"=59g "mol"^(-1)) , crystallizes with ccp. The edge length of the unit cell is 3.5 Å . If density of Ni crystal is 9.0g//cm^(3) , then value of Avogadro's number from the data is:

By X-ray diffraction it is found that nickel ("at mass"=59g "mol"^(-1)) , crystallizes in ccp. The edge length of the unit cell is 3.5 Å . If density of Ni crystal is 9.0g//cm^(3) , then value of Avogadro's number from the data is:

Edge length of unit cell of KCI is 629 pm and density is 1.989 g per cm^3 . Calculate Avogadro's number based on this X-ray diffraction data.

The density of KCl is 1.0893 g.cm^(-) and the length of a side of unit cell is 6.29082 Å . The value of Avogadro's number is:

An element with atomic mass 93 g mol^(-1) has density 11.5 g cm^(-3) . If the edge length of its unit cell is 300 pm, identify the type of unit cell.

An element with atomic mass 93 g mol^(-1) has density 11.5 g cm^(-3) . If the edge length of its unit cell is 300 pm, identify the type of unit cell.

An element with atomic mass 93 g mol^(-1) has density 11.5 g cm^(-3) . If the edge length of its unit cell is 300 pm, identify the type of unit cell.

Edge length of unit cell of KCI is 629 pm and density is 1.989 g cc^(-1) . Calculate Avagadro's number based on this X-ray diffraction data.