A 2kg block in on 5 kg block. The system of blocks falls freely due to gravity as shown. The net force on 5 kg block is:
`(Take g=10m//s^(2))`

In the figure shown, block of mass 2 kg is very long. Force of friction on 1 kg block is

In the figure shown, block of mass 2 kg is very long. Force of friction on 1 kg block is

What is the weight of a block of mass 10.5 kg ? Take g= 10 m s^(-2)

What should be the maximum value of M so that the 4 kg block does not slip over the 5 kg block : (Take g=10 m//s^(2) )

A block of mass 6 kg is kept on rough surface as shown in figure. Find acceleration and friction force acting on the block. (Take g=10m//s^(2) )

A block of mass 6 kg is kept on rough surface as shown in figure. Find acceleration and friction force acting on the block. (Take g=10m//s^(2) )

A lift is moving upwards with an acceleration of 2m//sec^(2) . Inside the lift a 4kg block is kept on the floor. On the top of it , 3kg block is placed and again a 2kg block is kept on the 3kg . Calculator : (i) contact force between 2kg block and the 3kg block. (ii) contact force between 4kg block and floor of the lift. Draw the free body diagrams properly & take g=10m//sec^(2)

A lift is moving upwards with an acceleration of 2m//sec^(2) . Inside the lift a 4kg block is kept on the floor. On the top of it , 3kg block is placed and again a 2kg block is kept on the 3kg . Calculator : (i) contact force between 2kg block and the 3kg block. (ii) contact force between 4kg block and floor of the lift. Draw the free body diagrams properly & take g=10m//sec^(2)

The coefficient of friction between 4 kg and 5 kg blocks is 0.2 and between 5 kg block and ground is 0.1 respectively. Choose the correct statement : (Take g=10m//s^(2) )

In figure shown if 2 kg block is moving at an acceleration 2 m//s^(2) , find the elongationin spring and acceleration of 4 kg block at this instant. Take g= 10m//s^(2) .