(dy)/(dx)=2y,(y>0)

Find the general solution of the differential equation (x+3y^2)(dy)/(dx)=y(y<0)

For the differential equation, find the general solution: (x+3y^2)(dy)/(dx) = y (y>0)

Find the particular solution of the following : (x+1)(dy)/(dx)=2e^(-y)-1,y(0)=0 .

Solve the following initial value problem: (x+1)(dy)/(dx)=2e^(-y)-1,y=(0)=0

Solve the initial value problem: (x+1)(dy)/(dx)=2e^(-y)-1,\ y(0)=0

Solve the following initial value problem: xy(dy)/(dx)=y+2,y(2)=0

For each of the following initial value problems verify that the accompanying functions is a solution. (i) x(dy)/(dx)=1, y(1)=0 => y=logx (ii) (dy)/(dx)=y , y(0)=1 => y=e^x (iii) (d^2y)/(dx^2)+y=0, y(0)=0, y^(prime)(0)=1 => y=sinx (iv) (d^2y)/(dx^2)-(dy)/(dx)=0, y(0)=2, y^(prime)(0)=1 => y=e^x+1 (v) (dy)/(dx)+y=2, y(0)=3 => y=e^(-x)+2

For each of the differential equations given in (x+2y^(2))(dy)/(dx)=y(y gt 0).

Solve the differential equation (x + 3y^2) (dy)/( dx) = y, (y gt 0) .