Home
Class 13
PHYSICS
[" A bar magnet "30cm" long is placed in...

[" A bar magnet "30cm" long is placed in the "],[" magnetic meridian with its North-pole "],[" pointing South.The neutral point is observed "],[" at a distance of "30cm" from its centre."],[" Calculate the pole strength of the magnet."],[" (Given,horizontal component of earth's field "],[B_(H)=0.34G)],[" Question Type: Single correct Type "],[" - "],[" 4."8.6Am]

Promotional Banner

Similar Questions

Explore conceptually related problems

A bar magnet 30cm long is placed in magnetic meridian with its north pole pointing south. The neutral point is observed at a distance of 30cm from its centre. Calculate the pole strength of the magnet. Given horizontal component of earth's field is 0*34G .

A bar magnet 30cm long is placed in magnetic meridian with its north pole pointing south. The neutral point is observed at a distance of 30cm from its centre. Calculate the pole strength of the magnet. Given horizontal component of earth's field is 0*34G .

A bar magnet 30 cm long is placed in the magnetic meridian with its north pole pointing geographical south . The neutral point is found at a distance of 30 cm from its centre . Calculate the pole strength of the magnet . Given B_(H) = 0.34 G .

A 30 cm long bar magnet is placed in the magnetic meridian with its north pole pointing south. The neutral point is obtained at a distance of 40 cm from the centre of the magnet. Pole strength of the magnet is (The horizontal component of earth’s magnetic field is 0.34 Gauss)

A 10 cm long bar magnet of magnetic moment 1.34 Am2 is placed in the magnetic meridian with its south pole pointing geographical south. The neutral point is obtained at a distance of 15 cm from the centre of the magnet. Calculate the horizontal component of earth’s magnetic field.

A short bar magnet of magnetic moment 1.2Am^(2) is placed in the magnetic meridian with its south pole pointing the north. If a neutral point is found at a distance of 20cm from the centre of the magnet, the value of the horizontal component of the earth's magnetic field is

A short bar magnet of magnetic moment 0*5JT^-1 is placed with its magnetic axis in magnetic meridian, with its north pole pointing geographic north. A neutral point is obtained at a distance of 0*1m from the centre of the magnet. Find the horizontal component of earth's magnetic field.

A small bar magnet is place in the magnetic meridian with its north pole pointing north . If a neutral point is formed on it perpendicular bisector at a distance of 10 cm from its centre , determine the magnetic moment of the magnet [ given , H=4xx10^(-5)T ]