" If "x-y+1=0" meets the circle "x^(2)+y^(2)+y-1=0" at "A,B" .Then the equation of the circle with "AB" as diameter is "

If x-y+1=0 meets the circle. x^(2)+y^(2)+y-1=0 at A and B , then the equation of the circle with A B as diameter is

If x - y + 1 = 0 meets the circle x^(2) + y^(2) + y - 1 = 0 at A and B , then the equation of the circle with AB as diameter is

If x-y+1=0 meets thwe cicle x^(2)+y^(2)+y-1=0 at a and b, then the equation of the circle with ab as diameter, is

The straight line x+y-1=0 meets the circle .x^(2)+y^(2)-6x-8y=0 at A and B . Then,the equation of : the circle of which AB is a diameter,is

The line 2x-y+6=0 meets the circle x^(2)+y^(2)-2y-9=0 at A and B. Find the equation of the circle on AB as diameter.

If the circle x^(2)+y^(2)+3x+2y+1=0 cuts another circles x^(2)+y^(2)+3x+4y+2=0 in A and B ,then the equation of the circle with AB as a diameter is

Let AB be the intercpet of the line y = x be the circle x^(2) + y ^(2) - 2x =0. Then the equation of the cirlce with AB as its diameter is :

The line 2x -y +6= 0 meets the circle x^2+y^2 -2y-9 =0 at A and B. Find the equation of the circle on AB as diameter.