किसी m द्रव्यमान की वस्तु जिसका वेग v है , का संवेग क्या होगा ?
` (a) (mv)^(2) (b) mv^(2) (c) ( (1)/(2)) mv^(2) (d) mv`

Calculate the frequency of paritcle wave, when the kinetic energy of a sub-atomic particle is 3.79 xx 10^(-27) J . Hint : KE = (1)/(2) mv^(2) lambda = (h)/(mv) , lambda = ( v)/( v) :. (v)/(v) = (h)/( mv), v= (mv^(2))/( h) = ( 2 xx ( 1)/(2) mv^(2))/( h)

Calculate the frequency of paritcle wave, when the kinetic energy of a sub-atomic particle is 3.79 xx 10^(-27) J . Hint : KE = (1)/(2) mv^(2) lambda = (h)/(mv) , lambda = ( v)/( v) :. (v)/(v) = (h)/( mv), v= (mv^(2))/( h) = ( 2 xx ( 1)/(2) mv^(2))/( h)

The SI unit of energy is J=kg m^(2)s^(-2) , that of speed v is ms^(-1) and of acceleration a is ms^(-2) . What of the formulae for kinetic energy (k) given below can you rule out on the basis of dimensional arguments (m stands for the mass of the body) : (a) K = m^(2)v^(2) (b) K = (1/2)mv^(2) ("c") K= ma (d) K = (3/16)mv^(2) (e) K=(1/2)mv^(2)+ma

The SI unit of energy is J=kg m^(2)s^(-2) , that of speed v is ms^(-1) and of acceleration a is ms^(-2) . What of the formulae for kinetic energy (k) given below can you rule out on the basis of dimensional arguments (m stands for the mass of the body) : (a) K = m^(2)v^(2) (b) K = (1/2)mv^(2) ("c") K= ma (d) K = (3/16)mv^(2) (e) K=(1/2)mv^(2)+ma

The SI unit of energy is J=kg m^(2)s^(-2) , that of speed v is ms^(-1) and of acceleration a is ms^(-2) . What of the formulae for kinetic energy (k) given below can you rule out on the basis of dimensional arguments (m stands for the mass of the body) : (a) K = m^(2)v^(2) (b) K = (1/2)mv^(2) ("c") K= ma (d) K = (3/16)mv^(2) (e) K=(1/2)mv^(2)+ma

For Question , calculat the block's speed asit passes through the equilibrium point ? Hint : E = K+U = (1)/(2) mv^(2) + (1)/(2) kx^(2) = (1)/(2) mv^(2) +0 . Calculate v