[" The work function of a metal is "],[2.3eV" and the wavelength of "],[" incident photon is "6.0times10^(-7)m" ."],[" Find maximum kinetic energy of "],[" photo electrons :- "]

The work function of a metal is 2.3 eV and the wavelength of incident photon is 4.8 xx 10 ^( -7) m. Find maximum kinetic energy of photo electrons

The work function of a metal is 3.4 eV. A light of wavelength 3000Å is incident on it. The maximum kinetic energy of the ejected electron will be :

The work function of a metal is 3.4 eV. A light of wavelength 3000Å is incident on it. The maximum kinetic energy of the ejected electron will be :

The work function of a mental is X eV when light of energy 2X eV is made to be incident on it then the maximum kinetic energy of emitted photo electron will be

The photoelectric work function of a metal surface is 2eV.When light of frequency 1.5xx10^(15) Hz is incident on it, the maximum kinetic energy energy of the photo electrons ,approximately is

A metal plate of area 1 xx 10^(-4) m^(2) is illuminated by a radiation of intensity 16m W//m^(2) . The work function of the metal is 5eV. The energy of the incident photons is 10eV. The energy of the incident photons is 10eV and 10% of it produces photo electrons. The number of emitted photo electrons per second their maximum energy, respectively, will be : [1 eV = 1.6 xx 10^(-19)J]

A metal plate of area 1 xx 10^(-4) m^(2) is illuminated by a radiation of intensity 16m W//m^(2) . The work function of the metal is 5eV. The energy of the incident photons is 10eV. The energy of the incident photons is 10eV and 10% of it produces photo electrons. The number of emitted photo electrons per second their maximum energy, respectively, will be : [1 eV = 1.6 xx 10^(-19)J]

A metal plate of area 1xx10^(-4)m^(2) is illuminated by a radiation 16 mW//m^(2) .The work function of the metal is 5eV.The energy of the incident photons is 10 eV and only 10% of it produces photo-electrons .The number of emitted photoelectrons per second and their maximum energy respectively will be

Initially, energy of incident photon was double of the work function of metal in a photoelectric effect. Finally energy of incident photon made 10 times of the work function. The ratio of maximum possible speed of photo electrons in initial & final case is alpha/beta . Then find minimum value of alpha :