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Sum of the series sum(k=0)^(n)""^(n)C(...

Sum of the series
`sum_(k=0)^(n)""^(n)C_(k)(-1)^(k)1/(a_(k))`
where `a_(k)=sum_(i=0)^(k)""^(k)C_(i)b_(i)`
where `b_(i)=sum_(j=0)^(i)""^(i)C_(j)((-2)/3)^(j)`
is

A

`1/(2^(n))`

B

`1/(3^(n))`

C

`1/(4^(n))`

D

`(3/4)^(n)`

Text Solution

Verified by Experts

The correct Answer is:
C
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