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If the number of five digit numbers with...

If the number of five digit numbers with distinct digit and 2 at the `10^(th)` place is 336 k, then k is equal to :

A

8

B

7

C

4

D

6

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The correct Answer is:
To solve the problem of finding the value of \( k \) in the number of five-digit numbers with distinct digits where 2 is fixed at the \( 10^{th} \) place, we can follow these steps: ### Step 1: Understand the structure of the five-digit number A five-digit number can be represented as \( ABCDE \), where \( B \) (the \( 10^{th} \) place) is fixed as 2. Thus, our number looks like \( A2CDE \). ### Step 2: Determine the possible digits for \( A, C, D, \) and \( E \) The digits available for selection are \( 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 \). Since 2 is already used in the \( 10^{th} \) place, we cannot use it again. Additionally, \( A \) cannot be 0, as it would not be a five-digit number. ### Step 3: Choose the first digit \( A \) The first digit \( A \) can be any digit from the set \( \{1, 3, 4, 5, 6, 7, 8, 9\} \) (8 options, since 0 and 2 are excluded). ### Step 4: Choose the remaining digits \( C, D, \) and \( E \) After selecting \( A \), we have 8 remaining digits (including 0 but excluding the digit chosen for \( A \) and 2). We need to choose 3 more digits from these remaining 8 digits. ### Step 5: Calculate the number of ways to choose and arrange the digits 1. Choose \( A \): 8 choices. 2. Choose 3 digits from the remaining 8 digits: \( \binom{8}{3} \). 3. The chosen 3 digits can be arranged in \( 3! \) ways. ### Step 6: Combine the counts The total number of five-digit numbers can be calculated as: \[ \text{Total} = 8 \times \binom{8}{3} \times 3! \] ### Step 7: Calculate \( \binom{8}{3} \) and \( 3! \) - \( \binom{8}{3} = \frac{8 \times 7 \times 6}{3 \times 2 \times 1} = 56 \) - \( 3! = 6 \) ### Step 8: Substitute back into the total count \[ \text{Total} = 8 \times 56 \times 6 = 2688 \] ### Step 9: Relate to the given equation We are given that this total equals \( 336k \): \[ 2688 = 336k \] ### Step 10: Solve for \( k \) \[ k = \frac{2688}{336} = 8 \] Thus, the value of \( k \) is \( 8 \).
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