Find the equation of the circle whose diameter is the common chord of the circles
`x^(2) + y^(2) + 2x + 3y + 1 = 0 and x^(2) + y^(2) + 4x + 3y + 2 = 0`

The equation of the circle whose diameter is the common chord of the circles x^(2) + y^(2) + 2x + 3y + 1 =0 and x^(2) + y^(2)+ 4x + 3y +2 = 0 is

The equation of the circle whose diamter is the common chord of the circles x^(2) + y^(2) + 2x + 3y + 2 = 0 " and" x^(2) + y^(2) + 2x - 3y - 4 = 0 is

The equation of the circle whose diameter is the common chord of the circles x^(2) + y^(2) + 2x+ 2y + 1= 0 and x^(2) + y^(2) + 4x+6y +6 = 0 is

The equation of the circel whose diameter is the common chord of the circles x ^(2) + y^(2) +2x +3y+2=0 and x ^(2) + y^(2) +2x -3y-4=0 is-

Determine equation of the circle whose diameter is the chord x+y=1 of the circle x^(2)+y^(2)=4

Find the equation fo the circle whose diameter is the common chord of the circles S -= x^2 + y^2 + 2x + 3y + 1 = 0 " ___"(1) and S^1 -= x^2 + y^2 + 4x + 3y + 2 = 0" __"(2)

The length of the common chord of the circles x^(2) + y^(2) + 2x + 3y + 1= 0 , x^(2) + y^(2) + 4x + 3y + 2 =0 is