The differential equation of co-axial system of circles `x^(2) + y^(2) -4 + lamda (2x + y - 5) = 0` is

The system of circles is x^(2) + y^(2) + 2 lambdax - 5 = 0 is

The equation to the line joining the centres of the circles belonging to the coaxial system of circles 4x^(2) + 4y^(2) - 12x + 6y - 3 + lambda (x + 2y - 6) = 0 is

The equation of the diameter of the circle x^(2)+y^(2)+2x-4y=4=0 that is parallel to 3x+5y-4=0 is

The equation of the diameter of the circle x^(2)+y^(2)+2x-4y-4=0 that is parallel to 3x+5y-4=0 is

The equation of the diameter of the circle x^(2) + y^(2) -4x-6y +3 = 0 that is perpendicular 2x + 5y-6 = 0 is