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Brine has a density of 1.2 g/cc. 40 cc o...

Brine has a density of 1.2 g/cc. 40 cc of it are mixed with 30 cc of water. The density of solution is

A

2.11 g/cc

B

1.11g/cc

C

12.2g/cc

D

20.4g/cc

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The correct Answer is:
To find the density of the solution formed by mixing 40 cc of brine with 30 cc of water, we can follow these steps: ### Step 1: Identify the densities and volumes - Density of brine (D1) = 1.2 g/cc - Volume of brine (V1) = 40 cc - Density of water (D2) = 1 g/cc (standard density of water) - Volume of water (V2) = 30 cc ### Step 2: Calculate the mass of brine To find the mass of the brine, we use the formula: \[ \text{Mass of brine} = \text{Density of brine} \times \text{Volume of brine} \] \[ \text{Mass of brine} = D1 \times V1 = 1.2 \, \text{g/cc} \times 40 \, \text{cc} = 48 \, \text{g} \] ### Step 3: Calculate the mass of water To find the mass of the water, we use the formula: \[ \text{Mass of water} = \text{Density of water} \times \text{Volume of water} \] \[ \text{Mass of water} = D2 \times V2 = 1 \, \text{g/cc} \times 30 \, \text{cc} = 30 \, \text{g} \] ### Step 4: Calculate the total mass of the solution Now, we add the masses of the brine and water to find the total mass of the solution: \[ \text{Total mass} = \text{Mass of brine} + \text{Mass of water} \] \[ \text{Total mass} = 48 \, \text{g} + 30 \, \text{g} = 78 \, \text{g} \] ### Step 5: Calculate the total volume of the solution Next, we find the total volume of the solution by adding the volumes of brine and water: \[ \text{Total volume} = V1 + V2 = 40 \, \text{cc} + 30 \, \text{cc} = 70 \, \text{cc} \] ### Step 6: Calculate the density of the solution Finally, we calculate the density of the solution using the formula: \[ \text{Density of solution} = \frac{\text{Total mass}}{\text{Total volume}} \] \[ \text{Density of solution} = \frac{78 \, \text{g}}{70 \, \text{cc}} \approx 1.11 \, \text{g/cc} \] ### Final Answer The density of the solution is approximately **1.11 g/cc**. ---
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MCGROW HILL PUBLICATION-LAWS OF MOTION, FRICTION AND ARCHIMEDES' PRINCIPLE-HIGHER ORDER THINKING QUESTIONS
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