The average force necessary to stop a hammer with 50 NS momentum in 0.05 s is

Options

A. 50 N
B. 100 N
C. 500 N
D. 1000 N

Answer

To find the average force necessary to stop a hammer with a momentum of 50 Ns in 0.05 seconds, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the relationship between momentum and force**:
The impulse (change in momentum) is equal to the average force multiplied by the time over which the force acts. This can be expressed mathematically as:
\[ J = F \cdot t \]
where \( J \) is the impulse (momentum), \( F \) is the average force, and \( t \) is the time.

2. **Identify the given values**:
- Momentum \( J = 50 \, \text{Ns} \)
- Time \( t = 0.05 \, \text{s} \)

3. **Rearrange the formula to solve for average force**:
From the impulse-momentum theorem, we can rearrange the formula to find the average force:
\[ F = \frac{J}{t} \]

4. **Substitute the known values into the equation**:
Now, substitute the values of \( J \) and \( t \) into the equation:
\[ F = \frac{50 \, \text{Ns}}{0.05 \, \text{s}} \]

5. **Calculate the average force**:
Perform the division:
\[ F = \frac{50}{0.05} = 1000 \, \text{N} \]

6. **Conclusion**:
The average force necessary to stop the hammer is:
\[ F = 1000 \, \text{N} \]