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At the centre of the earth , the value o...

At the centre of the earth , the value of g becomes

A

zero

B

unity

C

infinity

D

none of these

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The correct Answer is:
To determine the value of gravitational acceleration (g) at the center of the Earth, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Formula for g**: The acceleration due to gravity (g) at the surface of the Earth is given by the formula: \[ g = \frac{GM}{R^2} \] where \( G \) is the universal gravitational constant, \( M \) is the mass of the Earth, and \( R \) is the radius of the Earth. **Hint**: Remember that this formula applies at the surface of the Earth, where the entire mass of the Earth is exerting gravitational force. 2. **Considering the Earth as a Uniform Sphere**: For the purpose of this calculation, we assume the Earth is a perfect sphere with uniform density (\( \rho \)). The mass of the Earth can be expressed in terms of its density and volume: \[ M = \rho V \] where \( V \) is the volume of the Earth given by: \[ V = \frac{4}{3} \pi R^3 \] **Hint**: The volume of a sphere is crucial for relating mass and density. 3. **Substituting Volume into the Equation for g**: We can substitute the expression for volume into the equation for mass: \[ M = \rho \left( \frac{4}{3} \pi R^3 \right) \] Now substituting this back into the formula for g: \[ g = \frac{G \left( \rho \frac{4}{3} \pi R^3 \right)}{R^2} \] **Hint**: Simplifying the equation will help us understand how g changes with radius. 4. **Simplifying the Expression**: Simplifying the equation gives: \[ g = \frac{4}{3} G \rho R \] This shows that g depends on the density of the Earth and the radius. **Hint**: Notice that this expression still contains R, which we will evaluate for the center of the Earth. 5. **Evaluating g at the Center of the Earth**: At the center of the Earth, the radius \( R \) becomes 0. Substituting \( R = 0 \) into the equation: \[ g = \frac{4}{3} G \rho \cdot 0 = 0 \] **Hint**: Think about why the gravitational force would be zero at the center. 6. **Conclusion**: Therefore, the value of gravitational acceleration (g) at the center of the Earth is: \[ g = 0 \] **Final Answer**: The acceleration due to gravity at the center of the Earth is zero.
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MCGROW HILL PUBLICATION-GRAVITATION -HIGHER ORDER THINKING QUESTIONS
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