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The gravitational force between two ston...

The gravitational force between two stones of mass 1 kg each separated by a distance of 1 me tre in vacuum is

A

zero

B

`6.675xx10^(-5)N`

C

`6.675xx10^(-8)N`

D

`6.675xx10^(-11)N`

Text Solution

Verified by Experts

The correct Answer is:
D

`F=(Gm_(1)m_(2))/(d^(2))=(6.675xx10^(-11)xx1xx1)/((1)^(2))`
`=6.675xx10^(-11)N`
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