If the symbols have usual meanings then `(gR^(2))/(M)` represents

Options

A. G
B. `G^(2)`
C. `(1)/(G)`
D. `(1)/(G^(2))`

Explanation

To solve the problem, we need to analyze the expression \((gR^2)/M\) and determine what it represents, given that the symbols have their usual meanings in physics.

### Step-by-Step Solution:

1. **Understand the Symbols**:
- \(g\) = acceleration due to gravity at the surface of the Earth (approximately \(9.81 \, \text{m/s}^2\)).
- \(R\) = radius of the Earth (approximately \(6.371 \times 10^6 \, \text{m}\)).
- \(M\) = mass of the Earth (approximately \(5.972 \times 10^{24} \, \text{kg}\)).
- \(G\) = universal gravitational constant (\(6.674 \times 10^{-11} \, \text{N m}^2/\text{kg}^2\)).

2. **Recall the Formula for \(g\)**:
The acceleration due to gravity \(g\) at the surface of a planet can be expressed using the formula:
\[ g = \frac{GM}{R^2} \]
where \(G\) is the universal gravitational constant, \(M\) is the mass of the planet, and \(R\) is the radius of the planet.

3. **Rearranging the Formula**:
We can rearrange this formula to express \(G\):
\[ G = \frac{gR^2}{M} \]
This shows that \(G\) can be calculated if we know \(g\), \(R\), and \(M\).

4. **Substituting into the Expression**:
The expression given in the question is \(\frac{gR^2}{M}\). From our rearrangement, we see that:
\[ \frac{gR^2}{M} = G \]
Thus, the expression \(\frac{gR^2}{M}\) represents the universal gravitational constant \(G\).

5. **Conclusion**:
Therefore, the expression \(\frac{gR^2}{M}\) represents the universal gravitational constant \(G\).

### Final Answer:
\[ \frac{gR^2}{M} \text{ represents the universal gravitational constant } G. \]