`F_(g)` and `F_(e)` represent gravitational and electrostatic force respectively between electrons situated at a distance 10 cm. The ratio of `F_(g)//F_(e)` is of the order of

Options

A. `10^(36)`
B. `10^(43)`
C. `10^(-43)`
D. `10^(-36)`

Answer

C

Explanation

F_(g)=G((mxxm))/(r^(2))andF_(e)=(1)/(4piepsilon_(0))((exxe)/(r^(2)))`
So , `(F_(g))/(F_(e))=(Gm^(2))/(e^(2))xx4piepsilon_(0)`
`=(6.67xx10^(-11)xx(9.1xx10^(-31))^(2))/((1.6xx10^(-19))^(2))xx(1)/(9xx10^(9))`
`=10^(-43)`