If `theta` is smaller angle between force vector `vec(F)` and velocity vector `vec(v) ` then Fv cos `theta` represents

Options

A. work
B. power
C. kinetic energy
D. centripetal force

Explanation

To solve the question, we need to analyze the expression \( Fv \cos \theta \) where \( \theta \) is the angle between the force vector \( \vec{F} \) and the velocity vector \( \vec{v} \).

### Step-by-Step Solution:

1. **Understanding the Expression**:
- The expression \( Fv \cos \theta \) involves the force \( F \), the velocity \( v \), and the cosine of the angle \( \theta \) between the force and velocity vectors.

2. **Considering Small Angle**:
- Since \( \theta \) is described as a smaller angle, we can use the approximation that \( \cos \theta \approx 1 \) when \( \theta \) approaches 0.

3. **Substituting the Approximation**:
- Therefore, we can simplify the expression:
\[ Fv \cos \theta \approx Fv \cdot 1 = Fv \]

4. **Identifying the Physical Quantity**:
- The term \( Fv \) can be related to power. Power (\( P \)) is defined as the rate at which work is done, and it can be expressed as:
\[ P = \frac{W}{t} \]
- Work (\( W \)) done by a force is given by:
\[ W = F \cdot d \]
where \( d \) is the displacement in the direction of the force.

5. **Relating Power to Force and Velocity**:
- If we consider the displacement \( d \) over a time interval \( t \), we can express velocity as:
\[ v = \frac{d}{t} \quad \Rightarrow \quad d = vt \]
- Substituting this into the work formula gives:
\[ W = F \cdot vt \]
- Therefore, the power can be expressed as:
\[ P = \frac{F \cdot vt}{t} = Fv \]

6. **Conclusion**:
- Thus, we conclude that \( Fv \cos \theta \) represents power when \( \theta \) is a small angle.

### Final Answer:
The term \( Fv \cos \theta \) represents **power**.