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If p and E represent linear momentum and...

If p and E represent linear momentum and kinetic energy respectively, then the graph between E and pis correctly shown by

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To find the correct graph between linear momentum (p) and kinetic energy (E), we start with the definitions of kinetic energy and momentum. ### Step 1: Write the formulas for kinetic energy and momentum. - Kinetic Energy (E) is given by the formula: \[ E = \frac{1}{2} mv^2 \] - Momentum (p) is given by the formula: \[ p = mv \] ### Step 2: Express velocity (v) in terms of momentum (p). From the momentum equation, we can express velocity as: \[ v = \frac{p}{m} \] ### Step 3: Substitute the expression for velocity into the kinetic energy formula. Now, we substitute \(v\) into the kinetic energy equation: \[ E = \frac{1}{2} m \left(\frac{p}{m}\right)^2 \] This simplifies to: \[ E = \frac{1}{2} m \cdot \frac{p^2}{m^2} = \frac{p^2}{2m} \] ### Step 4: Analyze the relationship between E and p. From the equation \(E = \frac{p^2}{2m}\), we can see that kinetic energy (E) is directly proportional to the square of momentum (p): \[ E \propto p^2 \] This indicates that if we plot E against p, the graph will be a parabola opening upwards. ### Step 5: Determine the characteristics of the graph. - The graph will pass through the origin (0,0) because when \(p = 0\), \(E\) will also be \(0\). - The shape of the graph is a parabola because \(E\) is proportional to \(p^2\). ### Step 6: Identify the correct option from the given choices. Given the characteristics of the graph, we look for a graph that is a parabola opening upwards and passes through the origin. ### Conclusion: The correct graph between kinetic energy (E) and linear momentum (p) is a parabola that opens upwards, which corresponds to **Option 2**. ---

To find the correct graph between linear momentum (p) and kinetic energy (E), we start with the definitions of kinetic energy and momentum. ### Step 1: Write the formulas for kinetic energy and momentum. - Kinetic Energy (E) is given by the formula: \[ E = \frac{1}{2} mv^2 \] - Momentum (p) is given by the formula: ...
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