A body is under the action of two equal and op- posite forces, each 5 N. The body is displaced by 5 m, then the work done is

Options

A. 25 J
B. `-25 J `
C. 50 J
D. zero

Explanation

To solve the problem, we need to calculate the work done on a body that is acted upon by two equal and opposite forces, each of 5 N, while the body is displaced by 5 m.

### Step-by-Step Solution:

1. **Identify the Forces**:
- We have two forces acting on the body:
- Force 1 (F1) = 5 N in the positive direction.
- Force 2 (F2) = 5 N in the negative direction.

2. **Determine the Net Force**:
- Since the forces are equal in magnitude and opposite in direction, the net force (F_net) acting on the body is:
\[ F_{\text{net}} = F1 - F2 = 5 \, \text{N} - 5 \, \text{N} = 0 \, \text{N} \]

3. **Understand the Displacement**:
- The body is displaced by a distance (s) of 5 m.

4. **Calculate Work Done**:
- The formula for work done (W) is given by:
\[ W = F \cdot s \cdot \cos(\theta) \]
- Here, θ is the angle between the force and the direction of displacement. However, since the net force is zero (as established in step 2), we can conclude that:
\[ W_{\text{net}} = 0 \, \text{J} \]
- This is because, despite the displacement, the opposing forces cancel each other out, resulting in no net work done on the body.

5. **Conclusion**:
- Therefore, the total work done on the body is:
\[ W = 0 \, \text{J} \]

### Final Answer:
The work done is **0 Joules**.