When 1 g of water at `100^@`C gets converted into steam at the same temperature, the change in volume is approximately

Options

A. 1 cc
B. 1000 cc
C. 1500 cc
D. 1666 cc

Answer

To find the change in volume when 1 g of water at 100°C is converted into steam at the same temperature, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the mass of water**:
Given mass of water = 1 g.

2. **Determine the density of water**:
The density of water at 100°C is approximately 1 g/cm³.

3. **Calculate the volume of water**:
Using the formula for volume:
\[ \text{Volume of water} = \frac{\text{Mass of water}}{\text{Density of water}} = \frac{1 \text{ g}}{1 \text{ g/cm}^3} = 1 \text{ cm}^3 \]

4. **Determine the density of steam**:
The density of steam at 100°C is approximately 0.0006 g/cm³.

5. **Calculate the volume of steam**:
Using the formula for volume:
\[ \text{Volume of steam} = \frac{\text{Mass of steam}}{\text{Density of steam}} = \frac{1 \text{ g}}{0.0006 \text{ g/cm}^3} \approx 1666.67 \text{ cm}^3 \]

6. **Calculate the change in volume**:
The change in volume (ΔV) is given by:
\[ \Delta V = \text{Volume of steam} - \text{Volume of water} = 1666.67 \text{ cm}^3 - 1 \text{ cm}^3 = 1665.67 \text{ cm}^3 \]

7. **Final result**:
The change in volume when 1 g of water is converted to steam at 100°C is approximately:
\[ \Delta V \approx 1666 \text{ cm}^3 \]