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Two blocks of steel A and B, A being two...

Two blocks of steel A and B, A being two times heavier than B, are at `40^@C`. The ratio of heat content of A to B is

A

1

B

4

C

2

D

`1/2`

Text Solution

AI Generated Solution

The correct Answer is:
To find the ratio of heat content of two blocks of steel A and B, we can follow these steps: ### Step 1: Define the Mass of Each Block Let the mass of block B be \( m \). Since block A is two times heavier than block B, we can express the mass of block A as: \[ \text{Mass of A} = 2m \] ### Step 2: Define the Specific Heat Capacity Both blocks are made of steel, which means they have the same specific heat capacity. Let the specific heat capacity of both blocks be \( S \). ### Step 3: Calculate the Heat Content of Each Block The heat content (or heat capacity) of an object can be calculated using the formula: \[ \text{Heat Content} = \text{Mass} \times \text{Specific Heat Capacity} \times \text{Temperature} \] Since both blocks are at the same temperature (\( 40^\circ C \)), we can ignore the temperature in the ratio calculation. For block A, the heat content \( Q_A \) is: \[ Q_A = \text{Mass of A} \times S = (2m) \times S = 2mS \] For block B, the heat content \( Q_B \) is: \[ Q_B = \text{Mass of B} \times S = m \times S = mS \] ### Step 4: Calculate the Ratio of Heat Content Now, we can find the ratio of the heat content of block A to block B: \[ \text{Ratio} = \frac{Q_A}{Q_B} = \frac{2mS}{mS} \] When we simplify this, we find: \[ \text{Ratio} = \frac{2mS}{mS} = 2 \] ### Conclusion The ratio of the heat content of block A to block B is: \[ \text{Ratio} = 2 \]
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