Home
Class 10
PHYSICS
If temperature scale is changed from '^(...

If temperature scale is changed from `'^(@)C` to `'^(@)F`, the numerical value of specific heat

A

increase

B

decrease

C

remain unchanged

D

nothing can be said

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Topper's Solved these Questions

  • HEAT

    MCGROW HILL PUBLICATION|Exercise HIGHER ORDER THINKING QUESTIONS|15 Videos

  • GRAVITATION

    MCGROW HILL PUBLICATION|Exercise HIGHER ORDER THINKING QUESTIONS|25 Videos

  • HEATING AND MAGNETIC EFFECTS OF CURRENT

    MCGROW HILL PUBLICATION|Exercise HIGHER ORDER THINKING QUESTIONS|34 Videos

Similar Questions

Explore conceptually related problems

The specific rate constant for a reaction increases by a factor of 4, if the temperature is changed from 27^(@)C" to "47^(@)C . Find the activation energy for the reaction.

A new temperature scale uses X as a unit of temperature, where the numerical value of the temperature t_(x) in this scale is related to the absolute temperature T by t_(x) = 3T + 300 . If the specific heat of a material using this unit is 1400 J kg_(1)X_(1) its specific heat in the S.I. system of units is- c

140 grams of nitrogen absorbs 60 calories of heat without change in volume. If the temperature increases from 27^(@)C to 30^(@)C while doing so then what is the value of molar heat capacity ?

The linear equation that converts Fahrenheit (F) to Celsius (C ) is given by the relation, C=(5F-160)/(9) . (i) If the temperature is 86^(@) F , what is the temperature in Celsius ? (ii) If the temperature is 35^(@) C, what is the temperature in Fahrenheit ? (iii) If the temperature is 0^(@) C, what is the temperature in Fahrenheit and if the temperature is 0^(@) F, what is the temperature in Celsius ? (iv) What is the numerical value of the temperature which is same in both the scales ?

The temperature of an iron piece is heated from 30^@ C "to" 90^@ C . What is the change in its temperature on the fahrenheit scale and on the kelvin scale?

How much heat (in joule) is required to raise the temperature of 205 g of water from 21.2^(@)C to 91.4^(@)C . Specific heate of water is 4.18 J g^(-1) .^(@)C^(-1) Strategy : The specific heat of a substance is the amount of heat required to raise the temperature of 1g of the substance by 1^(@C . Thus Specific heat = (("Amount of heat in joules"))/(("Mass of substance in grams")("Temperature change in" .^(@)C)) Rearrangement gives. Amount of heat (q) = Mass of substance (m) xx Specific heat (c ) xx Temperature change (Delta T)