Home
Class 10
PHYSICS
A pendulum clock becomes...

A pendulum clock becomes

A

slower in winter

B

faster in summer

C

slower in summer and faster in winter

D

nothing can be decided

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding how a pendulum clock behaves in different seasons, we can break down the problem step by step. ### Step-by-Step Solution: 1. **Understanding the Pendulum Clock**: A pendulum clock operates based on the principle of a pendulum's motion, where the time period (T) of the pendulum is given by the formula: \[ T = 2\pi \sqrt{\frac{L}{g}} \] where \(L\) is the length of the pendulum and \(g\) is the acceleration due to gravity. 2. **Effect of Temperature on Length**: - In winter, the temperature is lower. Generally, materials contract in colder temperatures, which means that the length \(L\) of the pendulum will decrease. - In summer, the temperature is higher, causing materials to expand, which means that the length \(L\) of the pendulum will increase. 3. **Analyzing the Time Period**: - When the length \(L\) decreases (as in winter), the time period \(T\) will also decrease because \(T\) is directly proportional to the square root of \(L\). This means the pendulum will swing faster, and the clock will run faster. - Conversely, when the length \(L\) increases (as in summer), the time period \(T\) will increase, meaning the pendulum will swing slower, and the clock will run slower. 4. **Conclusion**: - Therefore, in winter, the pendulum clock becomes faster due to the decrease in length, and in summer, it becomes slower due to the increase in length. - The correct answer is: **The pendulum clock is slower in summer and faster in winter**. This corresponds to **Option 3**. ### Final Answer: The correct option is **Option 3: Slower in summer and faster in winter**. ---
Promotional Banner

Topper's Solved these Questions

  • HEAT

    MCGROW HILL PUBLICATION|Exercise HIGHER ORDER THINKING QUESTIONS|15 Videos
  • GRAVITATION

    MCGROW HILL PUBLICATION|Exercise HIGHER ORDER THINKING QUESTIONS|25 Videos
  • HEATING AND MAGNETIC EFFECTS OF CURRENT

    MCGROW HILL PUBLICATION|Exercise HIGHER ORDER THINKING QUESTIONS|34 Videos

Similar Questions

Explore conceptually related problems

A pendulum clock consist of aluminium rod connected to a bob. If the temperature of the surrounding becomes double , then the time period of pendulum

A pendulum clock keeps correct tiime at 30^(@) latitude. If a is taken to poles, then

A pendulum clock, keeps correct time at sea level, when taken to a place 1km below sea level, the clock loses or gain per day will be

A pendulum clock keeps correct time at 20^(@)C and coefficient of linear expansion of pendulum is 12xx10^(-6)//.^(@)C . If the room temperature increases to 40^(@)C , how many seconds the clock lose or gain per day?

A pendulum clock keeps correct time at 0^(@)C . Its mean coefficient of linear expansions is alpha//.^(@)C , then the loss in seconds per day by the clock if the temperature rises by t^(@)C is

A pendulum clock loses 24 sec a day if the temperature is 60^(@)C and gains 8 sec a day if the temperature is 40^(@)C .The temperature at which the clock will show correct time.

If temperature of a pendulum clock changes from theta_(1) to theta_(2) the fractional change in the period of a pendulum clock is

A pendulum clock shows correct time at 0^(@)C . At a higher temperature the clock.