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A simple pendulum suspended from the cei...

A simple pendulum suspended from the ceiling of a trans has a time period `T` when the train is at rest. If the train is accelerating uniformly at `a` then its time period

A

increase

B

decrease

C

become infinite

D

remain unaffected

Text Solution

Verified by Experts

The correct Answer is:
B
The bob is under the combined action of two accelerations: g acting vertically downwards and a acting along the horizontal.
`therefore` Resultant acceleration, `g. = sqrt(g^(2) + a^(2))`
`T = 2pi sqrt(L/g)`
Also, `T . = 2pi sqrt(L/g.) = 2pi = sqrt(L)/sqrt(g^(2) + a^(2))`
Which gives, `T . lt T` i.e., time period will decreases.
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