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With decrease in water vapour content in...

With decrease in water vapour content in air, velocity of sound

A

increases

B

decreases

C

remains constant

D

either (a) or (b)

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To solve the question regarding the effect of decreasing water vapor content in air on the velocity of sound, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Relationship Between Density and Velocity of Sound**: - The velocity of sound in a medium is influenced by the density of that medium. The general relationship is given by the formula: \[ v = \sqrt{\frac{K}{\rho}} \] where \( v \) is the velocity of sound, \( K \) is the bulk modulus of the medium, and \( \rho \) is the density of the medium. 2. **Effect of Water Vapor on Air Density**: - Water vapor is less dense than dry air. When water vapor is present in the air, it replaces some of the heavier nitrogen and oxygen molecules, leading to a decrease in the overall density of the air. - Therefore, when we decrease the water vapor content in the air, we are effectively increasing the density of the air. 3. **Analyzing the Change in Velocity**: - Since the density of the air increases when water vapor is removed, we can analyze the effect on the velocity of sound. - According to the relationship, if the density (\( \rho \)) increases, the velocity of sound (\( v \)) will decrease, because they are inversely related. 4. **Conclusion**: - Thus, with a decrease in water vapor content in the air, the density of the air increases, leading to a decrease in the velocity of sound. ### Final Answer: The velocity of sound will **decrease** with a decrease in water vapor content in the air. ---

To solve the question regarding the effect of decreasing water vapor content in air on the velocity of sound, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Relationship Between Density and Velocity of Sound**: - The velocity of sound in a medium is influenced by the density of that medium. The general relationship is given by the formula: \[ v = \sqrt{\frac{K}{\rho}} ...
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