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The magnification produced by a concave ...

The magnification produced by a concave mirror

A

is always more than one

B

is always less than one

C

is always equal to one

D

may be less than equal to or greater than one

Text Solution

AI Generated Solution

The correct Answer is:
To determine the magnification produced by a concave mirror, we need to analyze the different scenarios based on the position of the object relative to the mirror's focal point (F) and center of curvature (C). ### Step-by-Step Solution: 1. **Understanding Magnification**: - Magnification (m) is defined as the ratio of the height of the image (h_i) to the height of the object (h_o). - Mathematically, it is expressed as: \[ m = \frac{h_i}{h_o} \] 2. **Positioning the Object**: - The position of the object in relation to the focal point (F) and the center of curvature (C) of the concave mirror will affect the magnification. - There are three main positions to consider: - Object beyond C - Object at C - Object between F and C - Object at F 3. **Case 1: Object Beyond C**: - When the object is placed beyond the center of curvature (C), the image formed is real, inverted, and smaller than the object. - Hence, in this case, \( h_i < h_o \), leading to: \[ m < 1 \] 4. **Case 2: Object at C**: - When the object is placed at the center of curvature (C), the image formed is real, inverted, and of the same size as the object. - Therefore, \( h_i = h_o \), leading to: \[ m = 1 \] 5. **Case 3: Object Between C and F**: - When the object is placed between the center of curvature (C) and the focal point (F), the image formed is real, inverted, and larger than the object. - Thus, \( h_i > h_o \), leading to: \[ m > 1 \] 6. **Case 4: Object at F**: - When the object is placed at the focal point (F), the rays of light are parallel after reflection, and the image is formed at infinity. - This results in an undefined magnification since the height of the image cannot be determined. 7. **Conclusion**: - The magnification produced by a concave mirror can be less than 1, equal to 1, or greater than 1 depending on the position of the object. - Therefore, the correct answer is that the magnification may be less than, equal to, or greater than 1. ### Final Answer: The magnification produced by a concave mirror may be less than, equal to, or greater than 1.

To determine the magnification produced by a concave mirror, we need to analyze the different scenarios based on the position of the object relative to the mirror's focal point (F) and center of curvature (C). ### Step-by-Step Solution: 1. **Understanding Magnification**: - Magnification (m) is defined as the ratio of the height of the image (h_i) to the height of the object (h_o). - Mathematically, it is expressed as: \[ m = \frac{h_i}{h_o} \] ...
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