When an object is placed between F and 2F in front of a convex lens, the image formed is

Options

A. real and inverted
B. beyond 2F
C. magnified
D. all the above

Answer

To solve the question "When an object is placed between F and 2F in front of a convex lens, the image formed is", we will follow these steps:

### Step 1: Understand the Position of the Object
The object is placed between the focal point (F) and twice the focal length (2F) of a convex lens. This means that the object distance (u) is greater than the focal length (F) but less than twice the focal length (2F).

### Step 2: Use the Lens Formula
The lens formula is given by:
\[ \frac{1}{f} = \frac{1}{v} - \frac{1}{u} \]
Where:
- \( f \) = focal length of the lens
- \( v \) = image distance from the lens
- \( u \) = object distance from the lens

### Step 3: Determine the Nature of the Image
1. **Real or Virtual**: When the object is placed between F and 2F, the rays of light converge after passing through the lens, indicating that the image formed is real.

2. **Inverted or Upright**: The image formed by a convex lens when the object is placed between F and 2F is inverted.

### Step 4: Locate the Image
Since the object is between F and 2F, the image will be formed on the opposite side of the lens and will be located beyond 2F. This can be deduced from the lens formula and ray diagrams.

### Step 5: Magnification
The magnification (M) can be calculated using the formula:
\[ M = -\frac{v}{u} \]
Since the image is real and inverted, the magnification will be negative, but its absolute value will be greater than 1, indicating that the image is magnified.

### Step 6: Conclusion
From the analysis:
- The image is **real**.
- The image is **inverted**.
- The image is **magnified**.
- The image is located **beyond 2F**.

Thus, the final answer is that the image formed is **real, inverted, and magnified, located beyond 2F**.

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