In terms of wavelength of light `(lamda)`, intensity (I) of scattered light is related as

Options

A. `Iproplamda^(4)`
B. `Ipropu^(2)`
C. `Iprop1/lamda^(2)`
D. `Iprop1/lamda^(4)`

Answer

To solve the problem of how the intensity (I) of scattered light is related to the wavelength (λ) of light, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Relationship**: The problem states that we need to find how the intensity of scattered light depends on the wavelength. Generally, in scattering phenomena, it is observed that intensity is inversely related to the wavelength.

2. **Graphical Representation**: We can visualize the relationship by plotting a graph with intensity (I) on the y-axis and wavelength (λ) on the x-axis. As per the information given, as the wavelength increases, the intensity decreases.

3. **Identify the Nature of the Relationship**: From the graph, we can see that the intensity decreases as the wavelength increases. This indicates an inverse relationship. Thus, we can express this relationship mathematically as:
\[ I \propto \frac{1}{\lambda^n} \]
where \(n\) is a constant that we need to determine.

4. **Determine the Power**: Based on the provided transcript, it is indicated that the pattern of the graph suggests that the intensity is proportional to the inverse of the wavelength raised to the power of 4. Therefore, we can write:
\[ I \propto \frac{1}{\lambda^4} \]

5. **Final Relation**: To express this in a more formal way, we can write:
\[ I = k \cdot \frac{1}{\lambda^4} \]
where \(k\) is a constant of proportionality.

### Conclusion:
The intensity (I) of scattered light is inversely proportional to the fourth power of the wavelength (λ):
\[ I \propto \frac{1}{\lambda^4} \]