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How many electrons consitute a currenet ...

How many electrons consitute a currenet of one microampere ?

A

`6.25 xx 10 ^(6)`

B

`6.25 xx 10 ^(12)`

C

`6.25 xx 10 ^(9)`

D

`6.25 xx 10 ^(15)`

Text Solution

AI Generated Solution

The correct Answer is:
To find out how many electrons constitute a current of one microampere (1 µA) in one second, we can follow these steps: ### Step 1: Understand the given values We know that: - Current (I) = 1 microampere = \(1 \times 10^{-6}\) amperes - Time (t) = 1 second ### Step 2: Use the formula for electric current The formula for electric current is given by: \[ I = \frac{Q}{t} \] Where: - \(I\) is the current, - \(Q\) is the charge, - \(t\) is the time. Since we are considering the time to be 1 second, we can rewrite the formula as: \[ Q = I \times t \] ### Step 3: Substitute the values into the equation Substituting the values we have: \[ Q = (1 \times 10^{-6} \, \text{A}) \times (1 \, \text{s}) = 1 \times 10^{-6} \, \text{C} \] ### Step 4: Relate charge to the number of electrons The charge \(Q\) can also be expressed in terms of the number of electrons (\(n\)) and the charge of a single electron (\(e\)): \[ Q = n \times e \] Where: - \(e\) (the charge of one electron) = \(1.6 \times 10^{-19}\) coulombs. ### Step 5: Rearrange the equation to find the number of electrons We can rearrange the equation to solve for \(n\): \[ n = \frac{Q}{e} \] ### Step 6: Substitute the values of \(Q\) and \(e\) Now substituting the values we have: \[ n = \frac{1 \times 10^{-6} \, \text{C}}{1.6 \times 10^{-19} \, \text{C/electron}} \] ### Step 7: Calculate the number of electrons Calculating this gives: \[ n = \frac{1 \times 10^{-6}}{1.6 \times 10^{-19}} \approx 6.25 \times 10^{12} \] ### Final Answer Thus, the number of electrons that constitute a current of one microampere in one second is approximately: \[ n \approx 6.25 \times 10^{12} \, \text{electrons} \] ---
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