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A magnetic field...

A magnetic field

A

always exerts a force on a charged par ticle

B

never exerts a force on a charged particle

C

exerts a force, if the charged particle is moving along the magnetic field lines

D

exerts a force, if the charged particle is moving across the magnetic field lines

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AI Generated Solution

The correct Answer is:
To solve the question regarding the behavior of a charged particle in a magnetic field, we need to analyze the options provided based on the principles of electromagnetism. ### Step-by-Step Solution: 1. **Understanding the Magnetic Force on a Charged Particle**: The force \( F \) on a charged particle moving in a magnetic field is given by the formula: \[ F = Q \cdot V \cdot B \cdot \sin(\theta) \] where: - \( F \) is the magnetic force, - \( Q \) is the charge of the particle, - \( V \) is the velocity of the particle, - \( B \) is the magnetic field strength, - \( \theta \) is the angle between the velocity vector and the magnetic field direction. 2. **Analyzing Each Option**: - **Option 1**: "A magnetic field always exerts a force on a charged particle." - This is incorrect because if the charged particle is at rest (\( V = 0 \)) or moving parallel to the magnetic field lines (\( \theta = 0 \) or \( 180^\circ \)), then \( F = 0 \). - **Option 2**: "A magnetic field never exerts a force on a charged particle." - This is also incorrect because a magnetic field can exert a force on a charged particle when it is moving at an angle to the magnetic field lines (\( 0 < \theta < 180^\circ \)). - **Option 3**: "A magnetic field exerts a force on a charged particle if it is moving along the magnetic field lines." - This is incorrect as well. If the charged particle is moving along the magnetic field lines (\( \theta = 0 \)), the force \( F \) will be zero since \( \sin(0) = 0 \). - **Option 4**: "A magnetic field exerts a force if the charged particle is moving across the magnetic field." - This is correct. When the charged particle moves across the magnetic field lines, \( \theta \) is not \( 0 \) or \( 180^\circ \), thus \( \sin(\theta) \) is non-zero, and a force will be exerted on the particle. 3. **Conclusion**: Based on the analysis of the options, the correct answer is: **Option 4**: A magnetic field exerts a force if the charged particle is moving across the magnetic field.
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