A tuning fork vibrates with 2 vibrations in 0.4 seconds . Its frequency ( in Hz ) is

Options

A. 5
B. 6
C. 8
D. `0.8`

Explanation

To find the frequency of the tuning fork, we can use the formula for frequency, which is defined as the number of vibrations (or cycles) per second. The formula is:

\[ \text{Frequency (f)} = \frac{\text{Number of vibrations}}{\text{Time (in seconds)}} \]

### Step-by-Step Solution:

1. **Identify the number of vibrations**: The tuning fork vibrates 2 times.

2. **Identify the time period**: The time taken for these 2 vibrations is 0.4 seconds.

3. **Calculate the frequency**:
- We can substitute the values into the frequency formula:
\[ f = \frac{2 \text{ vibrations}}{0.4 \text{ seconds}} \]

4. **Perform the calculation**:
- First, divide 2 by 0.4:
\[ f = \frac{2}{0.4} = 5 \text{ Hz} \]

5. **Conclusion**: The frequency of the tuning fork is 5 Hz.

### Final Answer:
The frequency of the tuning fork is **5 Hz**.