A flow of `10^7` electrons per second in a conducting wire constitutes a current of

Options

A. `1.6 xx 10^(-26) A`
B. `1.6 xx 10^(26) A`
C. `-1.6 xx 10^(-12) A`
D. `1.6 xx 10^(-12) A`

Explanation

To find the current constituted by a flow of \(10^7\) electrons per second in a conducting wire, we can follow these steps:

### Step 1: Understand the relationship between current, charge, and time
The current \(I\) in a circuit is defined as the flow of charge \(Q\) per unit time \(T\):
\[ I = \frac{Q}{T} \]

### Step 2: Calculate the total charge \(Q\)
The total charge \(Q\) can be calculated using the formula:
\[ Q = N \cdot e \]
where:
- \(N\) is the number of electrons flowing per second (in this case, \(N = 10^7\)),
- \(e\) is the charge of a single electron, which is approximately \(1.6 \times 10^{-19}\) coulombs.

### Step 3: Substitute the values into the formula
Substituting the values into the equation for charge:
\[ Q = 10^7 \cdot (1.6 \times 10^{-19}) \]

### Step 4: Calculate \(Q\)
Now, we can calculate \(Q\):
\[ Q = 10^7 \cdot 1.6 \times 10^{-19} = 1.6 \times 10^{-12} \text{ coulombs} \]

### Step 5: Calculate the current \(I\)
Since the flow of electrons is per second, we can take \(T = 1\) second:
\[ I = \frac{Q}{T} = \frac{1.6 \times 10^{-12}}{1} = 1.6 \times 10^{-12} \text{ amperes} \]

### Final Answer
Thus, the current constituted by a flow of \(10^7\) electrons per second is:
\[ I = 1.6 \times 10^{-12} \text{ A} \]

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