A force of 60 N acting perpendicular to a force of 80 N can produce

Options

A. 20 N
B. 70 N
C. 100 N
D. 140 N

Explanation

To solve the problem of finding the resultant force when a force of 60 N acts perpendicular to a force of 80 N, we can follow these steps:

### Step 1: Identify the Forces
We have two forces:
- \( F_1 = 80 \, \text{N} \) (acting along the x-axis)
- \( F_2 = 60 \, \text{N} \) (acting perpendicular to \( F_1 \), along the y-axis)

### Step 2: Use the Pythagorean Theorem
Since the two forces are perpendicular to each other, we can use the Pythagorean theorem to find the resultant force \( F_R \).

The formula for the resultant force when two forces are perpendicular is:
\[ F_R = \sqrt{F_1^2 + F_2^2} \]

### Step 3: Substitute the Values
Now, substituting the values of \( F_1 \) and \( F_2 \) into the formula:
\[ F_R = \sqrt{(80 \, \text{N})^2 + (60 \, \text{N})^2} \]

### Step 4: Calculate the Squares
Calculating the squares of the forces:
\[ F_R = \sqrt{6400 \, \text{N}^2 + 3600 \, \text{N}^2} \]

### Step 5: Add the Squares
Now, add the squares:
\[ F_R = \sqrt{6400 + 3600} = \sqrt{10000 \, \text{N}^2} \]

### Step 6: Take the Square Root
Finally, take the square root:
\[ F_R = 100 \, \text{N} \]

### Conclusion
The resultant force when a force of 60 N acts perpendicular to a force of 80 N is **100 N**.

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